Question
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9
without repetition. - Each column must contain the digits
1-9
without repetition. - Each of the 9
3x3
sub-boxes of the grid must contain the digits1-9
without repetition.
A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character '.'
.
Example 1:
Input: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: true
Example 2:
Input: [ ["8","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note:
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
- The given board contain only digits
1-9
and the character'.'
. - The given board size is always
9x9
.
Difficulty:Medium
Category:HashTable
Analyze
Solution
class Solution {
public:
bool isValidSudoku(vector<vector<char>>& board) {
bool used[9] = {false};
for (int i = 0; i < 9; ++i) {
fill(used, used + 9, false);
// 1.Check each row
for (int m = 0; m < 9; ++m) {
if (!isUsed(board[i][m], used)) return false;
}
fill(used, used + 9, false);
// 2.Check each column
for (int n = 0; n < 9; ++n) {
if (!isUsed(board[n][i], used)) return false;
}
}
for (int i = 0; i < 3; ++i) {
for (int j = 0; j < 3; ++j) {
fill(used, used + 9, false);
// 3.Check 3*3 size
for (int m = 3 * i; m < 3 * i + 3; ++m) {
for (int n = 3 * j; n < 3 * j + 3; ++n) {
if (!isUsed(board[m][n], used)) return false;
}
}
}
}
return true;
}
bool isUsed(char ch, bool used[9]) {
if (ch == '.') return true;
if (used[ch - '1']) return false;
used[ch - '1'] = true;
return true;
}
};