Question
Given an array of citations sorted in ascending order (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
Note:
If there are several possible values for h, the maximum one is taken as the h-index.
Follow up:
- This is a follow up problem to H-Index, where
citations
is now guaranteed to be sorted in ascending order. - Could you solve it in logarithmic time complexity?
Difficulty:Medium
Category:Array
Analyze
Solution
class Solution {
public:
int hIndex(vector<int>& citations) {
int len_c = citations.size(), left = 0, right = len_c - 1;
while (left <= right) {
int mid_c = (right + left) / 2;
if (citations[mid_c] == len_c - mid_c)
return len_c - mid_c;
else if (citations[mid_c] > len_c - mid_c) {
right = mid_c - 1;
} else {
left = mid_c + 1;
}
}
return len_c - left;
}
};
Solution 2: Line Scan
class Solution {
public:
int hIndex(vector<int>& citations) {
vector<int>& c = citations;
for (int i = 1; i <= c.size(); ++i) {
if ( *(c.rbegin()+i-1) < i ) return i - 1;
}
return c.size();
}
};